Math Problem You Will Fail

[Amber]

 

[grate_biff]

25

 

[Kelvin]

70

 

[Greg Sacramento]

60

 

[Nick07]

15. The drink equals 10. The burger equals 5. The fries equal 1.

 

[Greg Sacramento]

5 + 1 * 10 = 5 + 10 = 15

That's right @Nick07

 

[threefirefour]

15. The drink equals 10. The burger equals 5. The fries equal 1.

Fries equal 2 each. 5+1+1=/=9.

 

[Julien87]

Thank you for the unsollicited advertisement

 

[Julien87]

15. The drink equals 10. The burger equals 5. The fries equal 1.

Oh, so 5 + 1 + 1 = 9

 

[threefirefour]

1) A+A+A=30
30/3=10
A=10

2) A[10]+B+B=20
20-A[10]=10
10/2=5
B=5

3)B[5]+C+C=9
9-B[5]=4
4/2=2
C=2

4) B[5]+C[2]•A[10]
B[5]+20
X=25

 

[grate_biff]

I did not see it was only one box of fries.
I guess 15 is correct, then. 5 + 1*10.

But why do I feel an urge to eat at McDonalds now?? I never do??

 

[vermillion]

I did not see it was only one box of fries.
I guess 15 is correct, then. 5 + 1*10.

But why do I feel an urge to eat at McDonalds now?? I never do??

I missed McDonalds and free MSG consumption.

 

[Julien87]

I did not see it was only one box of fries.
I guess 15 is correct, then. 5 + 1*10.

But why do I feel an urge to eat at McDonalds now?? I never do??

Yes, I was wrong too

 

[Kste Adams]

17
drink = 10
burger = 5
fries = 2
So a burger with a drink and fries = 10+5+2 = 17 (or way too many calories)

 

[threefirefour]

17
drink = 10
burger = 5
fries = 2
So a burger with a drink and fries = 10+5+2 = 17 (or way too many calories)

It's 5+2•10. That equals 70.

 

[Kste Adams]

It's 5+2•10. That equals 70.

Oops, misread the multiplication. However, in math multiplication is always done before addition unless you put the addition operation in parentheses. So 5+2*10 = 5+(2*10) = 25. If you want to come up with 70, you have to write it (5+2)*10.

I'm hungry...

 

[Lorac]

15

 

[Eclipse]

1 burger= 5
1 Fry = 2
1 drink = 10

5+2= 7
7 x 10 = 70

 

[attheedgeofscience]

Based on the, ahem, "creative" responses in this thread, I would say that perhaps the medical community will potentially have a new tool at their disposal in the future for tinnitus diagnostics: rather than testing for hearing loss when a new tinnitus patient shows up at the clinic, your local ENT might want to administer a math test instead. At least, it seems there is a strong correlation between mediocre math skills and tinnitus (if the responses in this thread are anything to go by...).

1st equation: 3x = 30, x = 10
2nd equation: x + 2y = 20, y = 5
3rd equation: y + 2z = 9, z = 2
4th equation: y + z * x = ?, ? = 5 + 2*10 = 5+ 20 = 25

Therefore: ? = 25

 

[Rubenslash]

Based on the, ahem, "creative" responses in this thread, I would say that perhaps the medical community will potentially have a new tool at their disposal in the future for tinnitus diagnostics: rather than testing for hearing loss when a new tinnitus patient shows up at the clinic, your local ENT might want to administer a math test instead. At least, it seems there is a strong correlation between mediocre math skills and tinnitus (if the responses in this thread are anything to go by...).

1st equation: 3x = 30, x = 10
2nd equation: x + 2y = 20, y = 5
3rd equation: y + 2z = 9, z = 2
4th equation: y + z * x = ?, ? = 5 + 2*10 = 5+ 20 = 25

Therefore: ? = 25

You are wrong in your 4th equation, there is only one fries whereas in the 3rd there are two fries for each element.

 

[attheedgeofscience]

You are wrong in your 4th equation, there is only one fries whereas in the 3rd there are two fries for each element.

I hear you (and I fully aware of the fact that there is only one box of french fries in the 4th equation)... But I would either go with my answer (the original one). Or simply state that set of equations cannot be solved. 2 boxes of french fries is a different variable to one box of french fries (consider it "chicken nuggets" - or whatever it is called). So essentially there is an unknown that cannot be solved for (perhaps that's why the title was written "math problem you will fail"). As I see it, anyway...

 

[vermillion]

3x=30, x=10 where x is the soda
10+2y=20, y=5 where y is one burger
y+2z+2z=9, z=1 where z is one box of fries
y+(zx)=5+10=15
?=15

 

[Lex]

Let:
s = soda
b = burger
f = fries

Equation 1:
s + s + s = 30
3s = 30
s = 30/3
s = 10

Equation 2:
s + b + b = 20
s + 2b = 20
10 + 2b = 20
2b = 20 - 10
2b = 10
b = 10/2
b = 5

Equation 3:
b + 2f + 2f = 9
b + 4f = 9
5 + 4f = 9
4f = 9 - 5
4f = 4
f = 4/4
f = 1

Solve:
b + f x s = ?
5 + 1 x 10
5 + (1 x 10)
5 + (10)
5 + 10
b + f x s = 15

 

[vermillion]

Are we sure that mathematics are safe for tinnitus?
Somebody told me that if you have tinnitus, studying (university, learning a foreign language etc) is brain stress and can worsen your condition, cause using your brain is promoting plasticity. It's like the sore muscle from working out. Any papers on this? @Aaron123 ?

 

[Lex]

Are we sure that mathematics are safe for tinnitus?

I love math, don't take it away from me.

 

[vermillion]

I love math, don't take it away from me.

i love languages. i want to study asian languages and visit the countries there and enjoy the street food. will my tinnitus agree? so far it has been an obnoxious greedy dream killer.

 

[Lex]

i love languages. i want to study asian languages and visit the countries there and enjoy the street food. will my tinnitus agree? so far it has been an obnoxious greedy dream killer.

Maybe, in time. Don't give up on your dreams. I know, easier said than done. But don't.

 

[dpdx]

15

 

[dpdx]

1) A+A+A=30
30/3=10
A=10

2) A[10]+B+B=20
20-A[10]=10
10/2=5
B=5

3)B[5]+C+C=9
9-B[5]=4
4/2=2
C=2

4) B[5]+C[2]•A[10]
B[5]+20
X=25

Nice try
But there is only one McDonalds fry so your last equation should be B(5)+ [ C (1) x A (10)] = 5 + ( 1 x 10) = 15

 

[threefirefour]

Nice try
But there is only one McDonalds fry so your last equation should be B(5)+ [ C (1) x A (10)] = 5 + ( 1 x 10) = 15

Hey just noticed that. Wow you might have won the thread.